Răspuns:
a) x³-2x²-5x+6= x³-x²-x²+x-6x+6=
= x²(x-1)-x(x-1)-6(x-1)=
= (x-1)×(x²-x-6)=
= (x-1)×(x²+2x-3x-6)
= (x-1)×(x+2)×(x-3)
b) x³-5x²+7x-3= x³-x²-4x²+4x+3x-3=
= x²(x-1)-4x(x-1)+3(x-1)=
= (x-1)×(x²-4x+3)=
= (x-1)×(x²-x-3x+3)=
= (x-1)×(x-1)×(x-3)=
= (x-1)²×(x-3)
