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a fost răspuns

desfaceti parantezele patrate
[ a(x+1)² supra b(x-1)]³

Răspuns :

Moisescuraluca
 [\frac{a(x+1) ^{2} }{b(x-1) ^{3} } ] = [ \frac{a* x^{2}+2x+1}{ x^{3}-1 }] = \frac{a* x^{2} +2x+1}{b* x^{3-3x ^{2}+3x-1 } } 

(x+1) ^{2} = x^{2} +2x+1 ^{2} (x-1) x^{3} = x^{3} -3x ^{2} +3x-1 x^{3} 

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