Răspuns:
c =22.63%
Explicație:
[tex]M_{NaCl} = 23 + 35.5 = 58.5 g/mol[/tex]
10 moli NaCl vor cantari 10*58.5 = 585 g NaCl = 0.585 kg NaCl
[tex]\frac{c}{100} =\frac{m_d}{m_s}[/tex]
[tex]m_s = 0.585 kg NaCl + 2 kg H_2O = 2.585 kg solutie NaCl[/tex]
[tex]m_d = 0.585 kg NaCl[/tex]
[tex]c = \frac{m_d*100}{m_s} = \frac{0.585 kg *100}{2.585 kg}=\frac{58.5 kg}{2.585kg} =22.63 %[/tex]
