Răspuns :
⇒(c)=30⇒conf T unghiului de 30 AB=BC/2=12/2=6 cm
T pitagora⇔AC²=12²-6² =108=36×3 AC=6√3 cm
sinC=6/12=1/2 cosC=6√3/12=√3/2 tgC=6/6√3=1/√3 ctgc=6√3/6=√3
T pitagora⇔AC²=12²-6² =108=36×3 AC=6√3 cm
sinC=6/12=1/2 cosC=6√3/12=√3/2 tgC=6/6√3=1/√3 ctgc=6√3/6=√3