Răspuns:
a+b+c+d+e=120-5
=115
a |__|
b |__| +1
c |__|+2
d |__|+3
e |__|+4 } 115
5p + 10=115
5p=115-10
5p=105
p=105÷5
p=21 (a)
21+1=22 (b)
21+2=23 (c)
21+3=24 (d)
21+4=25 (e)
numerele sunt 21, 22, 23 ,24 ,25
verificare 21+22+23+24+25=115
numerele sunt naturale consecutive
