[tex]253=\pi R(G+R)[/tex]
[tex]11=\pi R G[/tex]
Inlocuim a doua relatie in prima
[tex]253=11+\pi \ R^2[/tex]
[tex]242=\pi R^2[/tex]
[tex]R=\sqrt{\dfrac{242}{\pi}}=\dfrac{11\sqrt2}{\sqrt{\pi}}[/tex] Inlocuim in al doilea rand de sus
[tex]G=\dfrac{11}{\pi R}=\dfrac{11}{\pi\cdot\dfrac{11\sqrt2}{\sqrt{\pi}}}=\dfrac{1}{\sqrt{2\pi}}=\dfrac{\sqrt{2\pi}}{2\pi}[/tex]
