a. -2x= 2m x=-m
b. mx= 5 m ≠0 x= 5/m
c. mx=2m mx-2m =0 m( x -2) =0 pentru orice m≠ 0 solutie unica x=2
daca m=0 , orice numar real este solutie
d. mx -2x =1 x( m-2 ) =1 x= 1/( m-2 ) cu m≠2
daca m=2 2x-1 =2x -1=0 nu exista solutie
e. mx +m = - 2m mx = -3m daca m≠ 0 atunci x -3
daca m=0 0· x=0 are o infinitate de solutii , orice numar real verifica ecuatia
f. mx + x = m² -1
x( m+1) = ( m+1) ( m-1)
daca m+1≠0 , m≠ -1 solutia x= m+1
daca m=-1 ecuatia -x +x = 0 , adevarat 0=0 ecuatia are o infinitate de solutii in R