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Mutruc2003
a fost răspuns

impartiti numarul 1902 in parti invers  proportionale cu numerele : 5/6 , 4/5 , 3/4 , 2/3

Răspuns :

Renatemambouko
6k/5+5k/4+4k/3+3k/2=1902
72k+75k+80k+90k=114120
317 k = 114120
k=360
6x360/5=432
5x360/4=450
4x360/3=480
3x360/2=540

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