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Efectuati:
fractia 4x-16supra x+3 impartit la fractia 4xy-16ysupra 8x² + 24x

Răspuns :

CarMina03
[tex] \frac{4x-16}{x+3} : \frac{4xy-16y}{ 8x^{2}+24x} = \frac{4(x-4)}{x+3} : \frac{4y(x-4)}{8x(x+3)} = \frac{4(x-4)}{x+3}* \frac{8x(x+3)}{4y(x-4)} = \frac{8x}{y} [/tex]

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