Răspuns :
Fie x,y si z numerele in care se imparte numarul 376
x\8= y\12= z\27
faci suma numaratorilor supra suma numitorilor
x+y+z\8+12+27 =k
=> x= 8k
y=12k
z=27 k
dar x+y+z = 376 => 8k+12k+27k= 47K=376 => k=8
=> x=8x8=64
y=12x8= 96
z= 27x8 = 216
x\8= y\12= z\27
faci suma numaratorilor supra suma numitorilor
x+y+z\8+12+27 =k
=> x= 8k
y=12k
z=27 k
dar x+y+z = 376 => 8k+12k+27k= 47K=376 => k=8
=> x=8x8=64
y=12x8= 96
z= 27x8 = 216