Răspuns :
1. a(c+d)+b(c+d)=(a+b)(c+d)=20x30=600
2.2/x=y/7 =>> xy=6 =>> (xy-7)^100=(-1)^100=1
3.a) 2a+2b+2c=90 =>> a+b+c=45 ; b) b=30-c ; c=40-a
b=30-40-a =>>b=-10-a
a-10-a+40-a=45 =>.-a=45+10-40 =>> a=15
5. 10/100 x 270 = 27.
270+27=297=pretul initial
2.2/x=y/7 =>> xy=6 =>> (xy-7)^100=(-1)^100=1
3.a) 2a+2b+2c=90 =>> a+b+c=45 ; b) b=30-c ; c=40-a
b=30-40-a =>>b=-10-a
a-10-a+40-a=45 =>.-a=45+10-40 =>> a=15
5. 10/100 x 270 = 27.
270+27=297=pretul initial
4.Rezolvatii ecuatiile:
a)3x+1/√5=x+42/√20,x∈R
2x=42/√20-1/√5
2x=(42√5-√20)/√100
2x=(42√5-2√5)/10
2x=40√5/10
2x=4√5
x=2√5
b)(y+2)²+y=(3-y)²-5,x∈Q
y²+4y+4+y=9-6y+y²-5
+4y+4+y=9-6y-5
11y=0
y=0
5.
100%-10%=90%
270:90%=300 lei pretul initial
6 x=suma initiala
2x/3 + 15=1 zi
(x-2x/3 - 15) ×40%=(x/3 - 15) ×2/5=2x/15-6 = 1 2-a zi
2x/3+15+2x/15-6+27=x
15x-10x-2x=36×15
3x=540
x=180 lei
2x/15-6=2×180/15-6=24-6=18 lei a cheltuit a 2-a zi
a)3x+1/√5=x+42/√20,x∈R
2x=42/√20-1/√5
2x=(42√5-√20)/√100
2x=(42√5-2√5)/10
2x=40√5/10
2x=4√5
x=2√5
b)(y+2)²+y=(3-y)²-5,x∈Q
y²+4y+4+y=9-6y+y²-5
+4y+4+y=9-6y-5
11y=0
y=0
5.
100%-10%=90%
270:90%=300 lei pretul initial
6 x=suma initiala
2x/3 + 15=1 zi
(x-2x/3 - 15) ×40%=(x/3 - 15) ×2/5=2x/15-6 = 1 2-a zi
2x/3+15+2x/15-6+27=x
15x-10x-2x=36×15
3x=540
x=180 lei
2x/15-6=2×180/15-6=24-6=18 lei a cheltuit a 2-a zi