Răspuns:
Explicație pas cu pas:
c) n=3^23×4^23-2^21×6^21×6²=12^23-36×12^21=12^21(12²-6²)=
=12^21(12-6)(12+6)=12^21×6×6×3=12^21×12×3×3=12^22×3²=
=(3×12^11)²
d)n=3^2008(3³+2·3²+3+1)=3^2008×(27+18+4)=49·3^2008
=(7·3^1004)²
