va rog rapid am nevoie de ajutor dau coroana
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a)S, O, P=coliniare, deci <SOP=180°.
Stim ca MQ_I_NR=>m(<MON)=90°
=>m(<MOS)=180-(60+90)=30°
b) <NOP cu <ROS=opuse la varf=> m(<ROS)=60°.
Stim ca MQ_I_NR=>m(<ROQ)=90°
=>m(<SOQ)=60+90=150°