masa molara : HNO3 =1x1+1x14+3x16=63 , 1 mol HNO3 = 63 g , 63 g HNO3..... 1 g H .... 14 g N .....48 g O 100 g HNO3 ..... X g H .... Y g N....... Z g O , X = 100x1 supra 63 , X= 1,58 g H Y= 100x14 supra 63 ,X= 1400 supra 63 , Y=22,22 g N Z = 100x48 supra 63, Z = 4800 supra 63 , Z= 76,19 g O
