Vă rogggggggggggggggggggggggggg
![Vă Rogggggggggggggggggggggggggg class=](https://ro-static.z-dn.net/files/d48/bc841980bdce380512a8b12d9af11dee.jpg)
Răspuns:
2
Explicație pas cu pas:
daca z e o solutie a z²+z+1=0 (inmultind cu 'z-1') rezulta z³-1=0, adica z³=1 (z fiind doar una dintre radacinile complexe).
z²⁰¹³=(z³)⁶⁷¹=1, iar 1/z²⁰¹³=1
deci z²⁰¹³ + 1/z²⁰¹³ = 2