Răspuns :
7 caiete.....3penare=41
2caiete.......3penare=31
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5caiete.........../ =10
caietul= 10:5=2lei
2x2+3p=31=>3p=31-4 =>p=27:3=9 lei penarul
2caiete.......3penare=31
----------------------------------
5caiete.........../ =10
caietul= 10:5=2lei
2x2+3p=31=>3p=31-4 =>p=27:3=9 lei penarul
2c+3p=31/×7
7c+3p=41/×2
2c×7+3p×7=31×7
14c+21p=217(prima relatie)
7c×2+3p×2=41×2
14c+6p=82(a doua relatie)
14c+21p=217
14c+6p=82
/ +15p=135=)15p=135=)p=135:15=)p=9
2c+3p=31=)2c+3×9=31=)2c+27=31=)2c=31-27=)2c=4=)c=4:2=)c=2
Cu placere!
7c+3p=41/×2
2c×7+3p×7=31×7
14c+21p=217(prima relatie)
7c×2+3p×2=41×2
14c+6p=82(a doua relatie)
14c+21p=217
14c+6p=82
/ +15p=135=)15p=135=)p=135:15=)p=9
2c+3p=31=)2c+3×9=31=)2c+27=31=)2c=31-27=)2c=4=)c=4:2=)c=2
Cu placere!