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a fost răspuns

a=2^0+ 2^1+2^2+...+2^2018. aratati ca a= 2^2019-1​

Răspuns :

EnglishzzBoi

a=2^0+ 2^1+2^2+...+2^2018

a = 1+ 2^1 +2^2+ ...+ 2^2018

2a = 2^1+2^2+2^3+...+2^2018 + 2^2019

------------------------------------------(-)

2a-a = 2^1 +2^2+2^3+...+2^2018 + 2^2019 -( 1+ 2^1 +2^2+ ...+ 2^2018)

a = 2^2019 - 1