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Sfieayasmina
a fost răspuns

sa se efectueze b) (3⁵÷3³-2⁶÷2³)÷4⁰+5²​

Răspuns :

Salutare!

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Rezolvare

b) ( 3^5 ÷ 3^3 - 2^6 ÷ 2^3 ) ÷ 4^0 + 5^2 =

( 243 ÷ 27 - 64 ÷ 8 ) ÷ 4^0 + 5^2 =

( 9 - 8 ) ÷ 4^0 + 5^2 =

1 ÷ 4^0 + 5^2 =

1 ÷ 1 + 25 =

1 + 25 = 26

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Baftă! ❤

Flori200830

[tex]regula \: 1 ) \: {a}^{x \: } \times {a}^{y} = {a}^{x \ + \: y} [/tex]

[tex]regula \: 2) \: {a}^{x} \div {a}^{y} = {a}^{x - y} [/tex]

[tex]( {3}^{5} \div {3}^{3} - {2}^{6} \div {2}^{3} ) \div {4}^{0} + {5}^{2} [/tex]

[tex]( {3}^{5 - 3} - {2}^{6 - 3} ) \div 1 + 25[/tex]

[tex]( {3}^{2} - {2}^{3} ) \div 1+ 25[/tex]

[tex](9 - 8) \div 1 + 25 \\ 1 \div 1 + 25 = = = 26[/tex]

x⁰ = 1

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