Răspuns:
Explicație pas cu pas:
[(3x+1)/2]=5
5≤(3x+1)/2<6
5*2≤3x+1<6*2
10≤3x+1<12
10-1≤3x<12-1
9≤3x<11
9/3≤x<11/3
3≤x<11/3
x∈[3,11/3)
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[x+1/2]=(2x+7)/4
[x+1/2]=k k∈Z
(2x+7)/4=k
2x+7=4k
2x=4k-7
x=(4k-7)/2 (ii
Inlocuim x in relatia (ii
[(4k-7)/2+1/2]=k
[4k-7/2+1/2]=k
[4k/2-6/2]=k
[2k-3]=k
2k-3=k
2k-k=3
k=3 inlocuim k in relatia (ii
x=(4*3-7)/2
x=(12-7)/2
x=5/2
