Răspuns :
x²+2x+1+2(x²-2²)=3x²-9x-x+3+2⇔
⇔x²+3x²+2x+9x+x+2x²=-1-2+8+3+2⇔
⇔6x²+12x=10⇔
⇔6x(x-2)=10
ATAT RAMANE
⇔x²+3x²+2x+9x+x+2x²=-1-2+8+3+2⇔
⇔6x²+12x=10⇔
⇔6x(x-2)=10
ATAT RAMANE
x²+2x+1²+2(x²+2x-2x-4)=3x²-9x-x+3+2
x²+2x+1+2x²+4x-4x-8=3x²-10x+5
3x²+2x-7=3x²-10x+5
3x²-3x²+2x+10x=5+7
12x=12
x=12/12
x=1
x²+2x+1+2x²+4x-4x-8=3x²-10x+5
3x²+2x-7=3x²-10x+5
3x²-3x²+2x+10x=5+7
12x=12
x=12/12
x=1