Răspuns :
Răspuns:[tex]-\frac{cos(2x+1}{2}+C[/tex]
Explicație pas cu pas: Notam 2x+1= t
[tex]\int\ {\frac{sin(t)}{2} } \, dx \\\\=1/2 \int{sin(t)} \, dx \\\\1/2 (-cos(t))\\\\1/2 (-cos(2x+1))\\\\-\frac{cos(2x+1)}{2}\ +C[/tex]
Răspuns:[tex]-\frac{cos(2x+1}{2}+C[/tex]
Explicație pas cu pas: Notam 2x+1= t
[tex]\int\ {\frac{sin(t)}{2} } \, dx \\\\=1/2 \int{sin(t)} \, dx \\\\1/2 (-cos(t))\\\\1/2 (-cos(2x+1))\\\\-\frac{cos(2x+1)}{2}\ +C[/tex]