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Daryus44
a fost răspuns

efectuati,respectand ordinea efectuarii operatiilor: (x-3)(x la a doua-2x-3)-(-xla a doua)(1+3x)+(x+2)(3x-2).

Răspuns :

Lorena2000
(x-3)(x²-2x-3)-x²(1+3x)+(x+2)(3x-2)= (x³-2x²-3x-3x²+6x+9)-(x²+3x³)+(3x²-2x+6x-4)=
x³-5x²+3x+9-x²-3x³+3x²+3x-4= -2x³-2x²+6x+5

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