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Danielamireutaozerk3
a fost răspuns

Se dau C1 =20%, C2=40%; ms1/ms2=1/4.Sa se calculeze concentratia finala?​

Răspuns :

MihaiKappa

c1=20%

c2=40%

ms1/ms2=1/4 => ms2=4ms1 => ms1+ms2= 5ms1

c1=m1/s1 => m1 = c1*s1 = 20*1=20s1

c2=m2/s2=> m2=c2*4s1=160s1

c(final) = md(final)/ms(final) = 20s1+160s1/(s1+4s1) = 180s1/5s1 = 36%