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Mihneadumitrescu
a fost răspuns

x=(3^3×20+49×2^2-7)÷(3^2)^3^4^0+(1^2^3^4+4^3^0^5)=​

Răspuns :

Larisafrancu008

Răspuns:

x=(3^3•20+49•2^2-7÷(3^2)^3^4^0+(1^2^3^4+4^3^0^5)

x=(27•20+49•4-7)÷1+(1+1)

x=(540+196-7)÷1+2

x=(736-7)÷1+2

x=729÷1+2

x=729+2

x=731

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