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CaTa1233
a fost răspuns

2x²+2x-3=3x²-10x+5 Cum rezolv ???

Răspuns :

YuLiSsA
2[tex] x^{2} -3 x^{2} +2x+10x-3-5=0[/tex]
[tex]- x^{2} +12x-8=0/[/tex]·(-1)
[tex] x^{2} [/tex]-12x+8=0
Δ = 144-32
Δ=112
x=[tex] \frac{12+ \sqrt{112} }{2} [/tex]
x=[tex] \frac{12- \sqrt{112} }{2} [/tex]


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