construim CM _|_ AB -----> DC=AM=5cm
MB=AB-AM=4cm
In CMB triunghi dreptunghic in M cu B=60 ----> Masura lui C=30 -----> BC=2MB
BC=8
In CMB triunghi dreptunghic in M -----> T.Pitagora CM^2=BC^2-MB^2 ------->
CM^2=64-16
CM^2=48
CM=AD=4[tex] \sqrt{3} [/tex]
Aria=[tex] \frac{(AB+DC)x AD}{2} [/tex]
Aria=[tex] \frac{13X4 \sqrt{3} }{2} [/tex]
Aria=26[tex] \sqrt{3} [/tex]
