Răspuns :
[tex]f_{(x)}=3-2x\\
a=f_{( \sqrt{2} )}=3-2 \sqrt{2} \\
b=f_{ (\sqrt{2} )}=3+2 \sqrt{2} \\
M_g= \sqrt{a*b}\\
M_g= \sqrt{(3-2 \sqrt{2})-(3+2 \sqrt{2} ) }\\
M_g= \sqrt{3^2-(2 \sqrt{2})^2 } \\
M_g= \sqrt{9-4*2} \\
M_g= \sqrt{9-8}\\
M_g= \sqrt{1} \\
\bold{M_g=1}[/tex]