O piramida patrulatera regulata are latura de 12√3, si muchia de 12√6 . Aflati inaltimea , aria bazei , Aria laterala , Aria totala , si volumul.
latura=12√3 cm
muchia=12√6 cm
diagonala bazei=√[(12√3)²+(12√3)²]=12√6 cm
inaltimea=√(12√6)²-(6√6)²=√(864-216)=√648=18√2 cm
Ab=12√3x12√3=432 cm²
apotema=√[(12√6)²-(6√3)²]=√(864-108)=√756=6√21 cm
Al=(Pb×ap)/2=4x12√3x6√21/2=432√7 cm²
At=432+432√7=432(1+√7)
V=Abxh/3=432x18√2/3=2592√2 cm³
