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Nechitamagdale
a fost răspuns

Sa se rezolve in Q ecuatiile :
g) 3(x+4)²-2(x-1)(x+5)=3(2x+3)+(x+1)²
h) (3x-1)²-(5x-3)²=40x-4(2x+1)²

Răspuns :

Bia0708
g) 3(x+4)²-2(x-1)(x+5)=3(2x+3)+(x+1)²
3(x²+8x+16)-2(x²-x+5x-5)=6x+9+x²+2x+1
3x²+24x+48-2x²+2x-10x+10=x²+8x+10
+24x+48+2x-10x=+8x
16x-8x=-48
8x=-48
x=-6
Iar h) chiar nu il stiu sper ca te-am ajutat la g)
Renatemambouko
g) 3(x+4)²-2(x-1)(x+5)=3(2x+3)+(x+1)²
3(x²+8x+16)-2(x²-x+5x-5)=6x+9+x²+2x+1
3x²+24x+48-2x²+2x-10x+10=x²+8x+10
+24x+48+2x-10x=+8x
16x-8x=-48
8x=-48
x=-6
h) (3x-1)²-(5x-3)²=40x-4(2x+1)²
9x²-6x+1-25x²+30x-9=40x-16x²-16x-4
-6x+1+30x-9=40x-16x-4
24x-8=24x-4  
-8=-4  ceva e gresit  

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