1)
100% - 42,85% C - 2,38% H - 16,66% N = 38,11% O (aflat prin diferenta)
C = 42,85/12 = 3,571
H = 2,38/1 = 2,38
N = 16,66/14 = 1,19
O = 38,11/16 = 2,38 : 1,19
=> Fb = C3H2NO2
Fm = (C3H2NO2)n
n = 2 => Fm = C6H4N2O4
2)
C6H14
catena liniara aciclica
CH3-CH2-CH2-CH2-CH2-CH3
p s s s s p
catena ramificata saturata
p t s s p
CH3-CH-CH2-CH2-CH3
p CH3
