Răspuns:
[tex]g)( {3}^{2})^{4} = ({3})^{2 \times 4} = {3}^{8} \\ h)( {2}^{3})^{4} = (2)^{3 \times 4} = {2}^{12} \\ i)( {5}^{6} ) {}^{7} = (5) ^{6 \times 7} = {5}^{42} \\ j) {2}^{9} \times {7}^{9} = (2 \times 7) {}^{9} = {14}^{9} \\ k) {5}^{12} \times {3}^{12} = (5 \times 3) ^{12} = {15}^{12} \\ k) {7}^{21} \times {2}^{21} = (7 \times 5) ^{21} = {35}^{21} [/tex]
sper că te-am ajutat!!!
