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Calculati:


a) [tex]\frac{5}{\sqrt{5}} - \sqrt{5} + 0,(3) x/ori \frac{3}{5}[/tex]


b) [tex]-3\frac{1}{3} + {17,3} + [3,(6)] + {-1,7}[/tex]

(partea intreaga si partea fractionara), {17,3},{-1,7} sunt intre acolade


c) [tex]-\sqrt[7]{3} - (-\sqrt[5]{3}) + (-\sqrt[12]{3}) - (+\sqrt[2]{3})[/tex]

Răspuns :

Targoviste44

[tex]\it a)\ \dfrac{5}{\sqrt5}-\sqrt5+0,(3)\cdot\dfrac{3}{5}=\sqrt5-\sqrt5+\dfrac{3}{9}\cdot\dfrac{3}{5}=\dfrac{1}{5}\\ \\ \\ b)\ -3\dfrac{1}{3}+\{17,3\}+[3,(6)]+\{1,7\}=-3\dfrac{1}{3}+0,3+3+0,7=-\dfrac{1}{3}+1=\dfrac{2}{3}[/tex]

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