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a fost răspuns

a) (2x+1)(3x-5)-(x+3)^{2}-(x-4)(x-5)=
b) x^{2}-x-2=
c) x^{2}+10x+16=
d) x^{2}+2x-15=
e) ([tex] \sqrt{13-4 \sqrt{3} }[tex] - [tex] \sqrt{3}[tex]) ([tex] \sqrt{3}[tex]+1) - (3 [tex] \sqrt{2}[tex] - [tex] \sqrt{3}[tex]) (3 [tex] \sqrt{2}[tex] - [tex] \sqrt{3}[tex])

Răspuns :

Crisforp
Te ajut la a si la b ) ;
a) 6x^2 - 10x + 3x - 5 - ( x^2 + 6x + 9 ) - ( x^2 -4x -5x + 20 ) = 4x^2 -4x -34 ;
b) x^2 -2x + x - 2 = x( x- 2 ) + ( x - 2 ) = ( x - 2 )( x + 1 ) ;

Bafta !