Răspuns :
[tex]\it |3-2x|=5 \Rightarrow |2x-3|=5 \Rightarrow 2x-3\in\{-5,\ 5\}|_{+3} \Rightarrow 2x\in\{-2,\ 8\}|_{:2} \Rightarrow x\in[/tex]
A={x∈Z/ |x|≤√11}
=> -√11≤x≤√11
x∈Z∩ [-√11;√11]; x∈{-3; -2; -1; 0; 1; 2; 3}
A={-3; -2; -1; 0; 1; 2; 3}
B={x∈Z/ |3-2x|=5}
=> 3-2x=-5; 3-2x=5
2x=8=> x=4
2x=-2=>x=-1
B={-1; 4}
C={x∈Z/ 15≤x²<81
15≤4²; 9²=81, dar x²<81
=> x∈{4; 5; 6; 7; 8}
A={4; 5; 6; 7; 8}