Răspuns:
Na2SO3
M=(2x23gNa +32gS+3X16gO)/mol=126g/mol
126g sulfit contine....46gNa.....32gS....48hO
100G...................................x..............y............z
x= 100x46/126=36,5%Na
y=100x32/126=25,4%S
z= 100x48/126=38.1% O
se verifica x+y +z= 100
Explicație:
