Răspuns :
daca e isoscel ab=ac=6
triunghiul abc dreptunghic => cf.T.P ca BC²=AB²+AC²
BC²=6²+6²
BC²=36+36
BC²=72
BC=√72
BC=6√2
triunghiul abc dreptunghic => cf.T.P ca BC²=AB²+AC²
BC²=6²+6²
BC²=36+36
BC²=72
BC=√72
BC=6√2
Cf teoremei lui Pitagora I²= C²+c²=> I= √C²+c²
In cazul nostrum: I²= 6²+6²=>I²=2*6²=> I=√2*6²=6√2cm