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Amaliaenache10
a fost răspuns

daca x+2y=17 si y-3z=4 calculați
a) x+3y-3z=
b) 2x+5y-3z=
c) (3x+6y)+(2y-6z)=
d) (2x+4y)x(x+4y-6z)=
Va rog tema aceasta trebuie azi​

Răspuns :

Petro200474

x+2y=17

y-3z=4

...........(+)

x+2y+y-3z=17+4

x+3y-3z=21

2x+5y-3z=2(x+2y)+y-3z=2*17+4

=2x+4y+y-3z=34+4

=2x+5y-3z=38

(3x+6y)+(2y-6z)=3*17+2*4

=51+8

=59

(2x+4y)*(x+4y-6z)=2*17*(17+2*4)

=34*(17+8)

=34*25

=850

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