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a fost răspuns

x+[tex] \frac{2}{3} [/tex]-4 · [tex] \frac{5}{16} + \frac{2}{14} : \frac{12}{7} = 0[/tex]

Răspuns :

Munmnc
x+2/3-4*5/16+2/14*7/12=0
x+2/3-5/4+1/12=0
aducem la acelasi numitor
12x+8-15+1=0
12x-6=0
12x=6
x=6/12
x=1/2

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