Răspuns :
1) 3pe 3 - 1pe 3= 2 pe3
2pe3=72lei
72 : 2•3=108( lei)- restul din a doua zi
2)4pe4 - 1pe4= 3pe4
3 pe 4=108 lei
108::3•4=144( lei) - restul din prima zi
3)4 pe4 - 1 pe4=3pe4
3pe4=144 lei
144:3•4=192(lei)- suma pe care a avut-o Matei la inceput
Raspuns:Matei avut la inceput 192 lei
x=suma initiala
x/4= 1 zi
x-x/4=3x/4 =rest
3x/4 × 1/4=3x/16 = a 2-a zi
3x/4-3x/16=(12x-3x)16=9x/16 rest
9x/16 ×1/3 =3x/16 a 3-a zi
x/4+3x/16+3x/16+72=x
4x+3x+3x+1152=16x
6x=1152
x=192 lei
x/4= 1 zi
x-x/4=3x/4 =rest
3x/4 × 1/4=3x/16 = a 2-a zi
3x/4-3x/16=(12x-3x)16=9x/16 rest
9x/16 ×1/3 =3x/16 a 3-a zi
x/4+3x/16+3x/16+72=x
4x+3x+3x+1152=16x
6x=1152
x=192 lei