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Teo si BOgdan au fiecare cate o suma de bani .Teo are cu 10 lei mai mult decât BOgdan .Daca produsul sumelor celor doi este 2000;aflați cați lei are
fiecare.
X=10+y
X .y=2000.Va rog ajutatima

Răspuns :

Miky93
[tex]t+b=x \\\\ t=b+10 \\\\ t*b=2000 \\\\ b*(b+10)=2000 \\\\ b^2+10b=2000 \\\\ b^2+10b-2000=0 \\\\ a=1 \\\\ b=10 \\\\ c= -2000 \\\\ \Delta= b^2-4ac = 100-4*(-2000) \\\\ \Delta=100+8000 \to \boxed{8100} \\\\ y_1;y_2= \frac{-b\pm \sqrt{\Delta}}{2a}=\frac{-10 \pm \sqrt{8100}}{2} \\\\ y_1= \frac{-10-90}{2}=\frac{-100}{2} \to -50 \not \in N \\\\ y_2=\frac{-10+90}{2}=\frac{80}{2}\to \boxed{40} \in N \\\\\\ \boxed{\boxed{b=40 \ lei \ Bogdan}} \\\\ t=40+10 \\\\\\ \boxed{\boxed{t=50 \ lei \ Teo}}[/tex]

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