Sa consideram triunghiul dreptunghic ABC (m(<BAC)=90*) si D∈(BC) a.i. AD_|_BC.
CD=16cm si BD=36cm.
BC=AD+BD=16+36=52 (cm).
Aplic teorema catetei in ΔABC:
[tex]AB= \sqrt{BC*BD}= \sqrt{52*36}=12 \sqrt{13}(cm). \\ AC= \sqrt{BC*CD} = \sqrt{52*16}=8 \sqrt{13}(cm). [/tex]
