Răspuns:
2x-3x+1=5 -1x+1=5 -1x=5-1 -1x=4 -x=4÷1 -x=4
l x²-3x+1l=5
x²-3x+1=±5
caz 1
x²-3x+1=-5
x²-3x+1+5=0
x²-3x+6=0
Δ=(-3)²-4*1*6=
9-24= -15<0
Ecuatia nu admite solutii reale
Caz2
x²-3x+1=5
x²-3x+1-5=0
x²-3x-4=0
x1= -1
x2=4
Explicație pas cu pas:
