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Floreadumitruflorea3
a fost răspuns

Daca a=3 si b+c=5,calculeaza : a) b+c-a; b)4(a+1 ); c) 3(a+2)4(a- 1 ); d )2a+4b+4c ; e ) ab+ac.​

Răspuns :

Romanaalesia
a) 5-3=2
b) 4(3+1)=4•4=16
c) 3(3+1)•4(3-1)=3•4•4•2=12•8=96
d)2•3+4•5=6+20=26
e) a(b+c)=3•5=15
Anca3533
A). b+c-a
5-3=2

B). 4(a+1)=
4(3+1)=
4*4=16

C).3(a+2)*4(a-1)=
3(3+2)*4(3-1)=
3*5*5*2=
15*10=150

D si c sunt incomplete

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