Răspuns :
Adica coordinatele sunt egale
f(x)=y
x=y
=> f(x)=x
-x+2=x
2=2x
x=1
Punctul de coordonate: (1;1)
x = abscisa
y= ordonata (x=y)
A(x,x) ∈ Gf => f(x)=x
inlocuim :
f(x) =-x +2 =x => -x-x=-2 => -2x=-2 => x=1
A(1,1)
y= ordonata (x=y)
A(x,x) ∈ Gf => f(x)=x
inlocuim :
f(x) =-x +2 =x => -x-x=-2 => -2x=-2 => x=1
A(1,1)