[tex]25 {}^{7} \div 5 { }^{14} + 3 {}^{90} \div 27 {}^{29} = \\ ( {5}^{2} ) ^{7} \div 5 {}^{14} + 3 {}^{90} \div (3 {}^{3}) {}^{29} = \\ 5 {}^{2 \times 7} \div 5 {}^{14 } + 3 {}^{90} \div 3 {}^{3 \times 29} = \\ 5 {}^{14} \div 5 {}^{14} + 3 {}^{90} \div 3 {}^{87} = \\ 1 + 3 {}^{90 - 87} = 1 + 3 {}^{3} = \\ 1 + 27 = 28[/tex]
sper ca te am ajutat
