Răspuns :
[tex]\it\Big [\dfrac{7}{5}: \dfrac{14}{15}+ \dfrac{3}{2}:( \dfrac{9}{4}-1 \dfrac{1}{2})\Big]\cdot \dfrac{2}{7} = \Big [\dfrac{7}{5}\cdot \dfrac{15}{14}+ \dfrac{3}{2}:( \dfrac{9}{4}- \dfrac{^{2)}3}{\ 2})\Big]\cdot \dfrac{2}{7} =\\ \\ \\ = \Big(\dfrac{3}{2}+\dfrac{3}{2}\cdot\dfrac{4}{3}\Big)\cdot\dfrac{2}{7} =\Big(\dfrac{3}{2}+2\Big)\cdot\dfrac{2}{7}==\dfrac{7}{2}\cdot\dfrac{2}{7}=1[/tex]