Răspuns :
[tex]\it = [(81-16\cdot5):10+7^{13}:7^{12}]\cdot4=(\dfrac{1}{10}+7)\cdot4=\dfrac{71}{10}\cdot4=\dfrac{284}{10}=28,4[/tex]
[tex]\it = [(81-16\cdot5):10+7^{13}:7^{12}]\cdot4=(\dfrac{1}{10}+7)\cdot4=\dfrac{71}{10}\cdot4=\dfrac{284}{10}=28,4[/tex]