Fie R∈AS a.i. TR _|_ AS => VTRA-dreptunghi => VT=AR=3cm si VA=TR=5cm.
m(<TRS)=90* si m(<TSR)=60* => m(<RTS)=30*.
tg(<TSR)=tg60*=[tex] \sqrt{3} [/tex]=[tex] \frac{TR}{RS} =>RS= \frac{TR}{ \sqrt{3} }= \frac{5}{ \sqrt{3} } = \frac{ 5\sqrt{3} }{3} (cm). [/tex]
AS=AR+RS=[tex]3+ 5\sqrt{3}(cm). [/tex]
[tex] A_{VAST}= \frac{(VT+AS)*VA}{2}= \frac{6+ 5\sqrt{3} }{2}( cm^{2} ) .[/tex]
