Răspuns :
[tex]\it x^2-8x+3=0\\ \\ \\\sqrt{\Delta}=\sqrt{52}=\sqrt{4\cdot13}=2\sqrt{13} \\ \\ \\ x_{1,2}=\dfrac{8\pm2\sqrt{13}}{2}=\dfrac{2(4\pm\sqrt{13})}{2}=4\pm\sqrt{13}\\ \\ \\x_1=4-\sqrt{13},\ \ \ x_2=4+\sqrt{13}[/tex]
[tex]\it x^2-8x+3=0\\ \\ \\\sqrt{\Delta}=\sqrt{52}=\sqrt{4\cdot13}=2\sqrt{13} \\ \\ \\ x_{1,2}=\dfrac{8\pm2\sqrt{13}}{2}=\dfrac{2(4\pm\sqrt{13})}{2}=4\pm\sqrt{13}\\ \\ \\x_1=4-\sqrt{13},\ \ \ x_2=4+\sqrt{13}[/tex]