4.1(6)=[tex]4 \frac{16-1}{90} = 4\frac{15}{90} =4 \frac{3}{18} = 4\frac{1}{6} = \frac{25}{6} [/tex]
8,(3)=[tex]8 \frac{3}{9} =8 \frac{1}{3} = \frac{25}{3} [/tex]
5, 12, 6 i.p cu 10; [tex] \frac{25}{6} [/tex]; [tex] \frac{25}{3} [/tex]
⇒5*10=12*[tex] \frac{25}{6} [/tex]=6*[tex] \frac{25}{3} [/tex] (daca rezolvi calculele, observi ca intradevar acele produse sunt egale, deci acele numere sunt invers proportionale)
